Question:
The boundary value problem
x^2 y" - 2x y'+ 2 y = 0, subject to the boundary conditions
y(1) + a y'(1) = 1
y(2) + b Y'(2) = 2
has a unique solution if
1. a= -1, b=2
2. a=-1, b=-2
3. a=-2, b=2
4. a=-3, b=2/3
Solution:
The boundary value problem
x^2 y" - 2x y'+ 2 y = 0, subject to the boundary conditions
y(1) + a y'(1) = 1
y(2) + b Y'(2) = 2
has a unique solution if
1. a= -1, b=2
2. a=-1, b=-2
3. a=-2, b=2
4. a=-3, b=2/3
Solution:
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